16x^2-48x-58=0

Solution for 16x^2-48x-58=0 equation:

16x^2-48x-58=0

a = 16; b = -48; c = -58;
Δ = b2-4ac
Δ = -482-4·16·(-58)
Δ = 6016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6016}=\sqrt{64*94}=\sqrt{64}*\sqrt{94}=8\sqrt{94}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-8\sqrt{94}}{2*16}=\frac{48-8\sqrt{94}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+8\sqrt{94}}{2*16}=\frac{48+8\sqrt{94}}{32}
$